A person invests Rs 40,000 for 3 years at a certain rate of interest compounded annually. At the end of one year this sum amounts to RS 44000 . Calculate
(i) the rate of interest per annum.
(ii) the interest for the second year
(iii) the amount at the end of 3 years
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Answer:
(i)10% (ii) Rs 8,000 (iii) Rs 52,000
Step-by-step explanation:
Here,
Amonut= A
Principle= P
Interest=I
Rate= r/ rate
Time=T
(i) the rate of interest per annum.
I=P*T*R/100
4000=40,000*1 year*rate /100
4000=400*rate
4000/400=rate
10%=rate
(ii) the interest for the second year
We know,
I = P*T*R/100
I=40,000*2*10/100
I=8,00,000/100
I= Rs 8,000
(iii) the amount at the end of 3 years
I = P*T*R/100
I = 40,000*3*10/100
I= 12,00,000/100
I= Rs 12,000
A= I+P
A= Rs 12,000+ Rs 40,000
A= Rs 52,000
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