History, asked by Abhisheksingh5722, 2 months ago

A person invests Rs 5,600 at 14% p.a. compound interest for 2 years. Calculate:
(i) the interest for the first year; (ii) the amount at the end of the first year;
(iii) the interest for the second year, correct to the nearest ₹.


Correct answer = 10 thanks
Wrong Answer = Report ❌⚡

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Answers

Answered by adi894
3

Explanation:

please check this answer

Attachments:
Answered by Anonymous
5

\red{\bf{Given\: that,}}

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\bf\color{blue}{Principal}= ₹5600

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\bf\color{blue}{Rate} = 14 % per annum

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\bf\color{blue}{Time} = 2 years

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\sf\color{red}{(i)}The interest for the first year

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\boxed{\purple{\sf\frac{= (Principal × rate × Time)}{100}}}

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\boxed{\purple{\sf\frac{(5600 × 14 × 1)}{100}}}

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\bold{₹ 784}

\sf\color{red}{(ii)} The amount at the end of the first year

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\sf{= ₹ 5600 + ₹ 784}

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\sf{= ₹ 6,384}

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\textbf{So,}

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\tt\color{orchid}{Principal\: for \:the\: second \:year}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀\pink{\bigstar}★ \large\underline{\boxed{\bf\pink{= ₹ 6,384}}}

\\ \sf\color{red}{(iii)}The interest for the 2

nd year

\boxed{\purple{\sf\frac{= (6,384 × 14 × 1)}{100}}}

\\ \\ \\\bold{= ₹ 893.76}

\\ \\ \\ \\ The interest for the 2nd year, correct to the nearest

\underline{\boxed{\sf\green{= ₹ 894}}}

Thankyou :)

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