Question

a person invests rupees 10000for 3 years at a certain rate of intrestcompunded anually. at the end of first year this sum amounts to rupees11200. find rate of intrest, amount at the end of second year, intrest at the end of second year

Answer 1

Answer:

in that given question P=10,000

at the end of first year amount is A=11200

if the interest is compounded annually A= tha

11200=10000*(1+R/100)^1 that is n=1

112/100=(1+R/100)^1

(112/100)-1=R/100

R=12

amount at the end of second year is

A=P*(1+R/100)^n

A=10000*(1+12/100)^2

A=12544

interest is same R=12%