Math, asked by kiran5886, 11 months ago

a person invites a party of 13 guests to a dinner and places 8 of them at one table and the remaining 5 at the other, the table being round. in how many ways can be arrange the guests

Answers

Answered by MAN1111

0

in no way because 8 guest on one and five on one they are 13 guest that is equal to 8+5

Answered by shukla1597

4

Answer:

13!/40

Step-by-step explanation:

1/(8×5) × 13C8 × 5P5 × 8P8 = 13!/40

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