a person invites a party of 13 guests to a dinner and places 8 of them at one table and the remaining 5 at the other, the table being round. in how many ways can be arrange the guests
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in no way because 8 guest on one and five on one they are 13 guest that is equal to 8+5
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4
Answer:
13!/40
Step-by-step explanation:
1/(8×5) × 13C8 × 5P5 × 8P8 = 13!/40
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