Question

A person is flying a kite at an angle of elevation 60° The length of the thread is 30m .find the height of a flying kite from the ground

Answer 1

Question:

A person is flying a kite at an angle of elevation 60° The length of the thread is 30 m. Find the height of a flying kite from the ground.

Answer:

The height of the kite flying from the ground is 25.98 m.

Given:

The angle of elevation is 60°.

The length of the thread is 30 m.

To find:

The height of the kite from the ground.

Explanation:

Let, ABC is a right angled triangle in which, ∠B=90°, ∠C = 60° and CA = 30 m.

Hence we get,

Perpendicular = AB

Base = BC

Hypotenuse = AC=30 m.

We know that,

sin θ = $\frac{perpendicular}{hypotenuse}$

sin 60° = $\frac{\sqrt{3} }{2}$

∴ $\frac{AB}{AC}= \frac{\sqrt{3} }{2}$

⇒ $\frac{AB}{30} = \frac{\sqrt{3} }{2}$

⇒ $\frac{AB}{15}=\sqrt{3}$

⇒ AB = 1.732 × 15

         = 25.98 m.

∴ The height of the kite from the ground is 25.98 m.

Refer to the attachment for the figure and explanation.

Answer 2

The height of  a flying kite from the ground=$15\sqrt 3$ m

Step-by-step explanation:

In triangle ABC

Angle C=60 degree

AC=30 m

Let height of flying kite from the ground=h

$\frac{Perpendicular\;side}{Hypotenuse}=sin\theta$

Using the formula

$\frac{AB}{AC}=sin60$

$\frac{h}{30}=\frac{\sqrt 3}{2}$

Using the value of $sin 60^{\circ}=\frac{\sqrt 3}{2}$

$h=\frac{30\times \sqrt 3}{2}=15\sqrt 3 m$

The height of  a flying kite from the ground=$15\sqrt 3$ m

#Learn more:

https://brainly.in/question/15427939:Answered by Aksinghreigns