A person is given lenses of power +5D,-10D, +10D , -20 D considering a pair of lenses at a time, which two lenses he will select to get focal length of combination equal to -10cm.
10D, -20 D
-10 D, +10 D
+5 D, -10 D
-20 D, +5 D
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Toatal power, P= =P1+P2 and total length f is 1/5 =11/f+21/f
When lenses of 10 D and -5 D are taken , total power
P= =P1+P2
= 10 D-5 D = 5 D
Hence, focal length = 100/5=20cm
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