. A person is holding a bucket by applying a force of 10 N. He moves a horizontal distance of 5 m and then climbs up a vertical distance of 10 m Find the total work done by him.
Answers
Answer:
Work done by an object is defined as the force exerted on the object along the direction of displacement. In mathematical form, it is represented as:
⇒ Work Done = Force × Displacement × Cos Ф
Here, Ф is the angle between the direction of force and displacement.
In the first case, force exerted is 10 N and displacement is 5 m. The direction is horizontal to the direction of force. Hence the angle between them is 90°. Therefore Work done is given by:
⇒ Work Done = 10 N × 5 m × Cos 90°
Since Cos 90° = 0, we get work done to be zero.
Hence work done in first case is 0 J.
In the second case, force exerted remains the same but displacement is 10 m in the vertical direction. Since the direction is same, we get the angle between them to be 0°. Therefore work done is:
⇒ Work Done = 10 N × 10 m × Cos 0°
Since Cos 0° = 1, we get:
⇒ Work Done = 100 N.m or 100 J
Hence the net work or the total work done by the person holding the bucket is 100 J.
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Answer:-
Work done = Potential energy
= m g h
= 10 × 10 [ as F = mg = 10 ]
=100 J
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