A person is holding a bucket by applying a force of 10N. He moves a horizontal distance of 5m and then climbs up a vertical distance of 10m. Find the total work done by him
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Answer:
Total work done = 100 joule
Explanation:
Here , we consider two cases,
Case 1 :-
Person move horizontal distance
work done, W = FScosθ
= 10 × 5 × cos 90°
= 10 × 5 × 0
=0
Case 2 :-
person climb up vertical distance
work done, W = FScosθ
= 10 × 10 × cos 0°
= 100 J
Total work done = 0+100 =
= 100 J
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