A person is instructed to carry an important package from base camp B to summit A of a hill at a height of 1200 metres. He weighs 8000N and the package weighs 200N. How much work does the person so against gravity? What is the potential energy of the package at A if it is assumed to be zero at B?
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let m be mass of body
M be mass of object to be carried
then mg= 800N, m= 800÷9.8=81.63 Kg
& Mg=200N, M= 200÷g= 200÷9.8= 20.41 kg
workdone by person= (800N+200N)×1200m
= 12×10^5 Nm
Potential energy=(M+m)gh
= [81.63+20.41]×9.8×1200
=1199990.4 kgm2/s2
M be mass of object to be carried
then mg= 800N, m= 800÷9.8=81.63 Kg
& Mg=200N, M= 200÷g= 200÷9.8= 20.41 kg
workdone by person= (800N+200N)×1200m
= 12×10^5 Nm
Potential energy=(M+m)gh
= [81.63+20.41]×9.8×1200
=1199990.4 kgm2/s2
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