A person is listening to a tone of 500Hz ditting at a distance of 450Hz from the source of sound .What is the time interval b/w two succesive compressions from the source of sound
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Answered by
1
Given f=500 Hz
t=1/f
=1/500 s
=0. 002 s
t=1/f
=1/500 s
=0. 002 s
Answered by
1
The time interval between successive compressions is equal to the time period of the wave. And this time period is the reciprocal of frequency of the wave.
It is given by:
T = 1/frequency
T = 1/500
T = 0.002s
I hope this helps you.........
please mark my answer as brainliest answer.
It is given by:
T = 1/frequency
T = 1/500
T = 0.002s
I hope this helps you.........
please mark my answer as brainliest answer.
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