A person is painting his house walls. He stands on a ladder with a bucket containing paint in one hand and a brush in other. Suddenly the bucket slips from his hand and falls down on the floor. If the bucket with the paint had a mass of 6.0 kg and was at a height of 2.0 m at the time it slipped, how much gravitational potential energy is lost together with the paint ?
Concept of Physics - 1 , HC VERMA , Chapter " Work and Energy"
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Answered by
10
HEY!!
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⚫Mass of the bucket with the paint, m=6 kg
⚫Height at which the bucket is placed, h=2 m
⚫Potential energy of the bucket with the paint at the given height:-
P.E.=mgh
6×(9.8)×2
117.6 J
▶P.E. on the floor=0
▶Loss in potential energy=117.6−0
✔✔117.6 J≈118 J
_______________________________
⚫Mass of the bucket with the paint, m=6 kg
⚫Height at which the bucket is placed, h=2 m
⚫Potential energy of the bucket with the paint at the given height:-
P.E.=mgh
6×(9.8)×2
117.6 J
▶P.E. on the floor=0
▶Loss in potential energy=117.6−0
✔✔117.6 J≈118 J
Answered by
19
Given in the question :-
Mass of the bucket with paint (m) = 6kg
height at which the person is standing (h) = 2.0 m
Taking g= 9.8 m/s²
Using formula.
potential energy (U) = mgh
= 6 × 9.8 × 2.0
= 12 × 9.8
= 117.6 J
Hence the potential energy which is lost together with the paint is 117.6 J
Hope it Helps.
Mass of the bucket with paint (m) = 6kg
height at which the person is standing (h) = 2.0 m
Taking g= 9.8 m/s²
Using formula.
potential energy (U) = mgh
= 6 × 9.8 × 2.0
= 12 × 9.8
= 117.6 J
Hence the potential energy which is lost together with the paint is 117.6 J
Hope it Helps.
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