A person is pulling a bucket filled completely with water with the help of a light pulley, Mass of the bucket along with water contained in it is 20kg. The buoyant force by water is applied to bucket is 5N upwards and. Accelerations of bucket in water and air are(a in water=1m/s^2) and a in air=1.5m/s^2
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Work done by the person is the change in potential energy of the bucket and the rope.
Given, the rope has a uniform mass m. So the center of mass for the rope is at half of the length of the rope.
So, it will be at a distance h/2 from the bottom.
Work done = Change in PE of bucket+Change in PE of rope
W=Mgh+mg2h=(M+2m)gh
hope it will help u
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