A person is running on a horizontal circular path of radius are in the first round he wants with the speed V and takes time T if it takes time 2t covering the same track in second ground then its speed will be
Answers
Given : A person is running on a horizontal circular path of radius R in the first round
he went with the speed V and takes time T
it takes time 2T covering the same track in second round
To Find : its speed in 2nd round
and average speed in both rounds together
Solution:
Distance = Speed * Time
=> Distance = 2πR
Time = T
Speed = V
V * T = 2πR
=> V = 2πR/T
in second Round time is 2T
=> V' = 2πR/2T
=> V' = (1/2)(2πR/T)
=> V' = (1/2)V
=> V' = V/2
Speed in Second round = V/2
Total Distance in both rounds = 2 * 2πR
Total Time = T + 2T = 3T
Average speed in both rounds together = 2 * 2πR / 3T
= (2/3) (2πR/T)
= (2/3)V
= 2V/3
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