Question

A person is spinning with his two hands outstretched at the rate 4rad/ s.when he brings his hands close to his body,he spins at rate of 16 rad / s.the ratio of moment of inertia in the two cases successively is

Answer 1

I didn't understand your question

Answer 2

Answer:

The correct answer is 4:1

Explanation:

By Law of Conservation of Momentum,

I1 * w1 = I2 * w2

$I_{1} / I_{2} = w_{2} / w_{1}$

= 16/4 = 4/1 = 4:1