Question

A person is standing at a distance of 70 m from a church looking at its top. The angle of elevation is of 30°. Find the height of the church.
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Answer 1

Answer:

Let BC be the height of the church

consider person's height is negligible

In ΔABC

tan45 o = ABBC

⇒

Base

Perpendicular

1= 80BC

BC=80m

Hope it helps you