Question

a person is standing at a distance of 80m from a church looking at it's top. The angle of elevation is of 45 degrees. Find the height of church
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Answer 1

Answer :-

The height of the church is 80 metres.

Explanation :-

Let 'H' be the height of the church.

Given :

• Angle of elevation = 45°
• Distance from the church = 80 m

According to the question,

$= > \tan45</strong><strong>°</strong><strong> = \frac{</strong><strong>AB</strong><strong>}{</strong><strong>BC</strong><strong>} \\ = > 1 = \frac{</strong><strong>H</strong><strong>}{80} \\ = > </strong><strong>H</strong><strong> = 80 \: metres$

Hence, the height of the church is 80 metres.

Answer 2

Answer:

80m

Step-by-step explanation:

let AB be the height of the chruch.

let BC be the distance of the person from the chruch.

BC = 80M Given.

Angle ACB= 45°

tan45°=AB÷BC

1=AB÷80

AB=80m