Math, asked by aryanschauhan, 4 months ago

A person is standing in front of a tall building. He produces a sound and received his echo in 3 sec. How far is he standing from the building? Speed of sound is 330 m/s

Answers

Answered by himanshbishnoi
2

Answer:

TIME -3eec.

VELOCITY-330m/s

DISTANCE-?

V=2D/t ( in sound)

V×T=2D

330×3/2=D

495=D

Mark Me Brainlist

Answered by UniqueBabe
3

Answer:

Let’s assume that the student is standing at a distance x from the building.

The sound of his clap travels x metres to reach the building, and x metres again to reach the ears of the man, which leads to him hearing the echo.

So, total distance travelled by the waves (sound) is 2x. Time taken is 2s. Speed of sound is 340 m/s.

The data we have is:

Distance : 2x meters

Speed:340 m/s.

Time: 2s.

Distance=Speed × time

2x= 340× 2

x= 340m

Therefore, the distance is 340m.

Similar questions