A person is suffering from hypermetropia (or longsightedness). The near point of the person is 1.5 m (or 150 cm). Calculate the focal length and power of the convex lens used in his spectacles. Assume that the near point of the normal eye is 25 cm.
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hypermetropia can be corrected by using convex lens
Objects distance u = -25
Image distance v= -1. 5
Focal length = ?
using the formula
1/v-1/u = 1/f
= 1/150 - 1/25 = 1/f
1/150+1/25= 1/f
-1+6/150 = 1/f
f= 150/ 5 = 30 CM
f= 30cm
power p = 1/ f( in meter )
1/0.3
10/3 = 3.3 D
power = +3.3D
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