Question

A person is suffering from Hypermetropia. What is his near point and far point?



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Answer 1

A person who is suffering from hyprrmetropia his/her near point is at 50cm from his eye and far point is at almost 6m

Answer 2

Explanation:

The near-point of a person suffering from hypermetropia is at 50 cm from his eye.

The person needs a convex lens to rectify this defect.

Calculation of power of the lens:

This hypermetropic eye can see the nearby object kept at 25 cm clearly if the image is formed at its own near point i.e. 50 cm.

Object distance, u = -25 cm

Image distance, v = -50 cm

1/v – 1/u = 1/f

1/-50 – 1/-25 = 1/f

f = 50 cm

p = 100/f = 100/50 = 2D

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