Question

A person is throwing a ball in to the air one after the other he throws the second ball when first ball teach the highest point if he is throwing two ball every second how high do they rise

Answer 1

Hello !!
Here is your answer ...

$\underline{Given\: in \:the\: question}$:
=>He throws the next ball after the previous ball reaches at the top.

=>He is throwing 2 balls every second .

$\bold{Which \:means\: that \:ball\: reaches\: the}$
$\bold{the\: maximum \:height\:in \:O.5 \:second}$

Height=?

Final velocity (v) will be zero when the ball ball will be at top . So,
V=0m/s

Note:$\bold{Gravity\: is\: in \:opposite\: direction}$

$\underline{We\:know\:that,}$

v=u+(-g)t

u=v+gt

u=0+10*0.5 [g=10m/s² ]

u=5 m/s

Now,
v² - u² =2(-g)h
0² - 5² =-2*10*h
-25=-20*h
h=25/20
h=5/4
$\bold{\underline{h=1.25m}}$

Hope
It
Helps