Question

a person is throwing balls into the air one after other.he throws the second ball when first ball is at the highest point.if he is throwing two balls every second,how high do they rise?​

Answer 1

v=u+at

a=−g

t=1s

0=u−g

u=g

whers u is the inital velocity 

Distance travelled in 1s is the maximum height covered by the ball.

s=ut+21at2

s=g(1)+2g×12

=2g

=210

=5m