Question

a person is travelling in straight line if he covers a distance of 142.5m in 15 sec with an acceleration of 0.2m/s . find its initail velocity

Answer 1

Answer:

8m/s2

Explanation:

from second equation of motion

s=it+a(t)(t)÷2

142.5=u×15+[0.2×15×15]÷2

142.5=15u+22.5

142.5-22.5=15u

120÷15=u

u=8m/s

Answer 2

Explanation:

For this question we have been given

Displacement,s = 142•5 m

Total time taken,t = 15 sec

Acceleration,a = 0•2m/s^2

So we have an equation of motion

s=ut + 1at^2 where 'u' is initial velocity

2

→142•5=15u+0•5×0•2×(15)^2

→142•5=15u+22•5

→120=15u

→u=8m/s

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