Question

A person is unable to see items within 50 of his eyes.

(A) Name the defects of the vision. The person is suffering and the list of two possible reasons.

(B) Draw the diagram to show the defect in the above case.

(C)Mention the type of lens used by them for the improvement of the defects and calculate its power. Suppose that the close point of normal eyes is 25 cm.

(D)draw a labelled diagram for the correction of the defects in the above case.​

Answer 1

a) The person is suffering from hypermetropia.

b) ( refer the above attachment)

c) The type of lens used by him is convex of power +2 D.

d) ( refer the second attachment).

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Answer 2

• Defect is hypermetropia. It is due to small eyeball and extensive focal length of the eyelens.
• Draw the (1) and (2) diagram of hypermetropia of hypermetropia section of text book.
• The lens used is convex lens.Now,

    ⇒ y=50cm⇒0.5m                  D=25cm⇒0.25m

    ⇒ Power= y-D\yD⇒0.5-0.25\0.5*0.25⇒2D.

    ⇒ ∴ Power of convex lens= 2D

• The last diagram of the hypermetropic eye column in text book.

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