a person is unable to see the object distinctly place within 50 cm from his eyes calculate the power of the lens used by him. Assume that the near point for normal eye is 25cm.
Answers
A person suffering from hypermetropia can see distinct objects clearly but faces difficulty in seeing nearby objects clearly. It happens because the eye lens focuses the incoming divergent rays beyond the retina. This defect of vision is corrected by using a convex lens. A convex lens of suitable power converges the incoming light.
The given person will be able to clearly see the object kept at 25 cm (near point of the normal eye), if the image of the object is formed at his near point, which is given as 1 m.
Object distance, u = -25 cm
Image distance, v = -50cm
Focal length, f
Using the lens formula,
1/f = 1/v - 1/u
here u = -25 cm
v = -50cm
substituting & calculating for f, we get
f = +50cm = +0.5 m
Power P = 1/f = +2 D
Hope that resolves your problem.
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