Question

A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kilometers per hour for 30 minutes. If field has a length that is twice its width, find the area of the field in square meters.​

Answer 1

hi

your answer is here ,

Step-by-step explanation:

Let us first find the distance d jogged

distance = rate × time = (12 km / hr) × 30 minutes

= (12 km/hr) × 0.5 hr = 6 km

The distance of 6 km corresponds to 10 perimeters and therefore 1 perimeter is equal to

6 km / 10 = 0.6 km = 0.6 × 1000 meters = 600 meters

Let L and W be the length and width of the field.

The length is twice the width.

Hence

L = 2 W

The perimeter is 600 meters and is given by

2 (L + W) = 600

Substitute L by 2 W

2 (2 W + W) = 600

Simplify and solve for W

4 W + 2 W = 600

6 W = 600

W = 100

Find L

L = 2 W = 200

Find the area A of the rectangl

A = L * W = 200 * 100 = 20,000 square meters

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Answer 2

person jogged 10 times along the perimeter of a rectangle field at the rate of 12 kilograms per hour for 30 minutes.

If field has a length twice it's width, find the area of the field in square meters

:

Find how far he goes in a half hour at 12 km/hr

12 * 1%2F2 = 6 km or 6000 meters

He jogged 10 times around, therefore

6000/10 = 600 meters is the perimeter of the rectangle

:

let w = the width of the rectangle

"If field has a length twice it's width", therefore

2w = the length of the rectangle

:

The perimeter

2(2w) + 2w = 600

simplify, divide by 2

2w + w = 300

3w = 300

w = 300/3

w - 100 meters is the width

then

2(100) = 200 meters is the length

The area

A = 200 * 100

A = 20,000 sq meters is the area of the rectangle