Question

A person leaves his house and travelling at 4 km/hr reaches his office 10 minutes late. Had he travelled at 6 km/hr, he would have reached 20 minutes early. Find the distance from his house to the office.​

Answer 1

Answer:

Step-by-step explanation:

40 km

Answer 2

Answer:

HOPE IT WILL HELP YOU.

4=D/(T+10/60)---(1)

4=D/(T+10/60)---(1)7=D/(T-20/60)---(2)

4=D/(T+10/60)---(1)7=D/(T-20/60)---(2)Simplifies form : 24T-6D=-4 -----(3)

4=D/(T+10/60)---(1)7=D/(T-20/60)---(2)Simplifies form : 24T-6D=-4 -----(3)21T-3D=7-------(4)

4=D/(T+10/60)---(1)7=D/(T-20/60)---(2)Simplifies form : 24T-6D=-4 -----(3)21T-3D=7-------(4)Solving (3) and (4)

4=D/(T+10/60)---(1)7=D/(T-20/60)---(2)Simplifies form : 24T-6D=-4 -----(3)21T-3D=7-------(4)Solving (3) and (4)T=1, D=14/3

4=D/(T+10/60)---(1)7=D/(T-20/60)---(2)Simplifies form : 24T-6D=-4 -----(3)21T-3D=7-------(4)Solving (3) and (4)T=1, D=14/3Answer is a) 14/3

Step-by-step explanation:

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