a person lends rs300 to A at 4% and rs540 to B at 6% for the same time. if the total amount that he gets at the end is rs1032.what is the time?
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Money lent to A+B = (300 + 540) = Rs. 840
Amount received = Rs. 1032
Interest received = Rs. 1032 - Rs.840 = Rs. 192
Interest on Rs. 300 lent to A for 1 year = 300×1×4100
= Rs. 12
Interest on Rs.540 lent to B for 1 year = 540×6×1100
= Rs. 36
Total yearly interest = Rs.(12+36) = Rs.48
If interest is Rs. 48, time = 1 year
If interest is Rs. 192, time = 192/48 = 4 years .
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Amount received = Rs. 1032
Interest received = Rs. 1032 - Rs.840 = Rs. 192
Interest on Rs. 300 lent to A for 1 year = 300×1×4100
= Rs. 12
Interest on Rs.540 lent to B for 1 year = 540×6×1100
= Rs. 36
Total yearly interest = Rs.(12+36) = Rs.48
If interest is Rs. 48, time = 1 year
If interest is Rs. 192, time = 192/48 = 4 years .
PLEASE MARK AS BRAINLIEST ANSWER :)
Answered by
1
Money lent to A+B = (300 + 540) = Rs. 840
Amount received = Rs. 1032
Interest received = Rs. 1032 - Rs.840 = Rs. 192
Interest on Rs. 300 lent to A for 1 year = 300×1×4100 = Rs. 12
Interest on Rs.540 lent to B for 1 year = 540×6×1100 = Rs. 36
Total yearly interest = Rs.(12+36) = Rs.48
If interest is Rs. 48, time = 1 year
If interest is Rs. 192, time = 192/48= 4years.
HOPE IT HELPS .
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