Math, asked by juttarakeysh, 11 months ago

a person lends rs300 to A at 4% and rs540 to B at 6% for the same time. if the total amount that he gets at the end is rs1032.what is the time?​

Answers

Answered by kshemanthca4
1
Money lent to A+B = (300 + 540) = Rs. 840

Amount received = Rs. 1032

Interest received = Rs. 1032 - Rs.840 = Rs. 192



Interest on Rs. 300 lent to A for 1 year = 300×1×4100
= Rs. 12



Interest on Rs.540 lent to B for 1 year = 540×6×1100
= Rs. 36





Total yearly interest = Rs.(12+36) = Rs.48

If interest is Rs. 48, time = 1 year

If interest is Rs. 192, time = 192/48 = 4 years .
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Answered by fatema1236
1

Money lent to A+B = (300 + 540) = Rs. 840

Amount received = Rs. 1032

Interest received = Rs. 1032 - Rs.840 = Rs. 192

Interest on Rs. 300 lent to A for 1 year = 300×1×4100 = Rs. 12

Interest on Rs.540 lent to B for 1 year = 540×6×1100 = Rs. 36

Total yearly interest = Rs.(12+36) = Rs.48

If interest is Rs. 48, time = 1 year

If interest is Rs. 192, time = 192/48= 4years.

HOPE IT HELPS .

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