Question

a person lent Rs 6000 at 8% simple interest. find the interest and also the amount that he gets at the end of one year.

Answer 1

S.I=RS 480
Amount=RS 6480

Answer 2

SOLUTION :

Principal (P) = Rs 6000         (given)

Rate of Interest (R) = 8% per annum          (given)

Time (T) = 1 year         (given)

To be found :-

The Simple Interest(S.I) and the Amount(A)

we know that,

$S.I = \frac{P \times R \times T }{100}$

$S.I = \frac{6000 \times 8 \times 1 }{100}$

$S.I = 480$

∴ Simple Interest (S.I) = Rs 480

Now,

Amount(A) = Principal(P) + Simple Interest (S.I)

Amount(A) = Rs 6000 + Rs 480

Amount(A) = Rs 6480

Hence,

Simple Interest (S.I) = Rs 480

Amount(A) = Rs 6480