A person lifts a heavy load to a vertical height of 2,0 m in 3 seconds. If he/she had done this more slowly in seconds, the work on the load would have been:
Answers
Answered by
3
Answer:
lesser
Explanation:
he/she had done this more slowly in seconds, the work on the load would have been lesser than old value
Answered by
1
Explanation:
if He would have been slower then also work would be the same.
see how,
force(f)=m*a
acceleration (a)=(v-u)/t
displacement (s)=v*t
for time t1
work=force*displacement
=m*a*s
=(m*(v-u)/t1)*(v*t1)
t would be cancelled
now when time decreases let we take time t2
work=force*displacement
=m*a*s
=(m*(v-u)/t2)*(v*t2)
my answer is definitely correct.
if you are confused then solve it in your copy to feel it more clearly.
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