Question

A person lifts a luggage of 15 kg from the ground and puts it on hs head 1.5m above the ground.the amount of work done by him on the luggage is

Answer 1

amount of work done is zero because the angle between his displacement and force applied is 90°.
and
work done = force × displcement ×cos theta
work done = force × displacement × cos 90°
work done = zero

Answer 2

Answer:

The work done by porter on the luggage​ is 225 J

Explanation:

Given,

A porter lifts a luggage of mass = 15 kg from the ground.

It's on his head 1.5 m above the ground.

To find: The work done by him on the luggage​

Solution:

here, Force is due to the weight of the luggage.

i.e F = mg , where m = mass of luggage and g = accerleration due to gravity

or, F = 15 * 10 = 150 N

Work done can be given as:

W = F * s

where, F = force and s = displacement i.e 1.5 m

W = 150 * 1.5 = 225 J

Therefore, The work done by porter on the luggage​ is 225 J.