Physics, asked by MdAnupMalik9762, 11 months ago

A person looks at different trees in an open space with the following details. Arrange the trees in decreasing order of their apparent sizes. Tree
Height(m)
Distance from the eye(m)
A
2.0
50
B
2.5
80
C
1.8
70
D
2.8
100

Answers

Answered by krishanyadav1310974
0

Answer:

the answer is 2.o this is a right answer you don't write in exam

Explanation:

Answered by bhuvna789456
0

Arrangement of the trees in descending order is A, B, C and D.

Explanation:

Given data in the question :

Let the tree with the eyes make a visual angle θ .

θ = $\frac{\text { Tree height }}{\text { Distance from the eye }}$

For the tree,  

$\begin{equation}\mathrm{A}: \frac{2.0}{50}=0.04\end

$\begin{equation}\mathrm{B} : \frac{2.5}{80}=0.03125\end

$\begin{equation}\mathrm{C} :\frac{1.8}{7.0}=0.0257\end

$\begin{equation}\mathrm{D} :\frac{2.8}{100}=0.028\end

$\begin{equation}\theta_{\mathrm{A}}>\theta_{\mathrm{B}}>\theta_{\mathrm{D}}>\theta_{\mathrm{C}}\end

The more value of angle θ, the larger the tree, the apparent size.

Thus, the decreasing-order arrangement is A, B, D, and C.

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