Question

A person loses 75% of his money in the first bet, 75% of the remaining in the second and 75% of the remaining in the third bet and returns home with Rs. 2 only. What will his initial money? ​

Answer 1

Answer:

His initial money is Rs.128

Step-by-step explanation:

Let his initial money be Rs.x

Given : In the first bet he loses 75 % of x

So , the money lost in the first bet is 0.75x

Now , the money left with him after first bet is

Initial money - money lost in first bet

x - 0.75x

0.25x

In the second bet he loses 75% of 0.25x

So, the money lost

in the second bet is 0.1875x (0.75 × 0.25x)

Now,

the money left with him after second bet is

remaining money - money lost in second bet

0.25x - 0.1875x

0.0625x

In the third bet he loses 75% of 0.0625

So, the money lost

in the third bet is 0.046875x (0.75 × 0.0625)

Now,

the money left with him after third bet is

remaining money - money lost in third bet

0.0625x - 0.046875x

0.015625x

Now, according to question they have given he takes Rs.2 home

So, 0.015625x = 2

0.015625

x = ---------------

2

x = Rs.128

Answer 2

Answer:

128

Step-by-step explanation:

if initial money is x

after 1st bet  remaining 25% = x/4

after 2nd bet remaining 25% of x/4 = x/16

after 3rd bet remaining 25% of x/16 = x / 64

given x / 64 = 2

so x = 128