Question

A person moves 30 m north and then 20m towards east and finally 30√2m in south-west direction. The displacement of the person from the origin will be

Answer 1

When he walks 30m north, vector obtained is 30j^Further When he walks 20m east, vector obtained is 20i^ Further he walks 30√2 south west, which cannot be written either along x-axis or y-axis so we take components of this movement along x-axis and y-axis

along x-axis = 30√2×cos45°= 30i^(towards west)

along Y-axis = 30√2×sin45°=30j^(towards south)

Now net movement, 30j^+20i^-30j^-30i^ = -10i^ This shows the displacement of 10m towards west from origin

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