Question

A person moves 30 m north then 20 m towards east and finally 30√2 in south west direction. The displacement of the person from the origin will be?

Answer 1

Answer:

The person moves 30m North ⇒ 30 j

The person then moves 20m east ⇒ 20 i

Then he moves 30√2m SW

Thus on resolving the vector, we get along x-direction as

30√2cos45° and along y-direction as 30√2sin45° (as SW is 45° from west)

= -30 i -30 j (As on drawing the vectors in x-y we see they are pointing in the negative x and negative y directions)

Thus net displacement is 20 i + (-30 i) + 30 j + (-30 j)

= -10 i

= 10 m in the West direction.