Question

A person moves 30m east, 20m north and 30√2 south west.find the displacement from the origin

Answer 1

Hey Mate here us ur answer

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Displacement is the shortest distance between two points. In this case, the starting and finish point.

You need not make it very complex, you can solve it using simple Pythagorean Theorem,

Sum of Square of Sides = Square of Hypotenuse

Simply draw a diagram of the path taken by the person.



We nee AD,

At C, he turned South West, so it would be 45 Degrees to the current path of Travel, And It would normally intersect AB at 45 Degrees.

Now in Triangle BCE

We know Angle C is 45, and Angle E is 45 as Angle B is 90 (180–90–45)

As Angles E and C are 45, that implies, sides CB and BE are also identical in length. 20 kms. And say Side CE = a

==> a^2 = 20^2 + 20^2

==> a = 20√2

As we know, CD = 30√2

==>ED = CD-CE = 30√2 - 20√2 = 10√2

Now in Triangle ADE, ED = 10√2 and AE = (30–20) = 10

And we know Angle A = 90

S0,

DE^2 = AE^2 + AD^2

==> (10√2)^2 = 10^2 + AD^2

==> AD = Sqrt(200–100) = 10 m

Good Luck

Answer 2

heya mate. here is your answer .
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