Question

A person moves 30m north then 30 m east then 30√2 south west his displacement from the original position is

Answer 1

Answer:

The displacement is 15√2.

Answer 2

Step-by-step explanation:

First 30 m north =>30j cap

Then 30 m east => 30i cap

30√2 south east => 30√2( cos225°i cap + sin225°j cap ) => 30√2( -1/√2i cap -1/√2 j cap) => -30i cap -30j cap. Hence the net displacement is 30j cap+30i cap -30i cap -30j cap =>0. Hope it helps you.