a person moves 7.5m towards West and then 400cm towards North find the distance and the displacement.
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2
given
7.5m west and 400cm = 4m north
hence distance is the total path covered
7.5 + 4 = 11.5 m = 1150 cm
but displacement is the shortest path covered
now consider a right angled triangle
the displacement we need to calculate will be the hypotenuse
7.5 is adjacent side
4 is the opposite side
therefore
(hypo)^2 = (adj)^2 + (opp)^2
= (7.5)^2 + (4)^2
= 56.25 + 16
= 72.25
(hypo)^2 = 72.25
hypo = root 72.25
hypo = 8.5 m = 850 cm
therefore displacement = 8.5 m = 850 cm
hope it helps
can u mark me as brainliest plz
7.5m west and 400cm = 4m north
hence distance is the total path covered
7.5 + 4 = 11.5 m = 1150 cm
but displacement is the shortest path covered
now consider a right angled triangle
the displacement we need to calculate will be the hypotenuse
7.5 is adjacent side
4 is the opposite side
therefore
(hypo)^2 = (adj)^2 + (opp)^2
= (7.5)^2 + (4)^2
= 56.25 + 16
= 72.25
(hypo)^2 = 72.25
hypo = root 72.25
hypo = 8.5 m = 850 cm
therefore displacement = 8.5 m = 850 cm
hope it helps
can u mark me as brainliest plz
RevelliSowmya422:
priyanka
Answered by
0
8.5 is ur answer for this qns
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