Question

A person moves 8 km towards north and then 6 km towards east.Calculate distance and displacement
​

Answer 1

Answer:

Let the east direction to be

i

^

and north direction be

j

^

.

Thus displacement of the man

S

=8

i

^

+6

j

^

So, magnitude of displacement ∣

S

∣=

6

2

+8

2

=

100

=10 m

Answered By

Answer 2

Distance = AO + AB = 8km + 6km = 14 km

Displacement = O to B ( shortest path)

In right triangle AOB,

OB² = AO² + AB² [as, H² = B² + P²]

$OB = \sqrt{ {8}^{2} + {6}^{2} } \\ OB= \sqrt{64 + 36} \\ OB = \sqrt{100} = 10km$

Thus, displacement = 10 km