A person moves a distance of 3km towards east, then 2 km towards north and then 3.5 km towards east. Find- (a) The distance covered by the person (b) The displacement of this motion
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Answered by
336
Hello friend
Here's your answer
Distance is the length of the path taken/covered by an object. It is a scalar quantity (scalar quantities are the ones which only have magnitude like time)
Here distance will be 3km+2km+3.5km
=8.5km
Displacement is the length of the shortest path between the initial and the final position. It is a vector quantity (Vector quantities are the ones which have both magnitude,called speed and direction)
Here displacement can be found out using Pythagorean theorem
Displacement ²=2²+6.5²
Displacement=√4+42.25
Displacement=√46.25=6.8(approx)
Hope it helps!
Here's your answer
Distance is the length of the path taken/covered by an object. It is a scalar quantity (scalar quantities are the ones which only have magnitude like time)
Here distance will be 3km+2km+3.5km
=8.5km
Displacement is the length of the shortest path between the initial and the final position. It is a vector quantity (Vector quantities are the ones which have both magnitude,called speed and direction)
Here displacement can be found out using Pythagorean theorem
Displacement ²=2²+6.5²
Displacement=√4+42.25
Displacement=√46.25=6.8(approx)
Hope it helps!
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wvaish:
My pleasure :)
Answered by
53
Answer:
a) Distance will be
3km + 2km + 3.5km = 8.5km
b) Displacement
Using Pythagoras theorem
= 2² + 6.5²
= _/4 + 42.25
= _/46.25
= 6.8
Explanation:
hope it'll help you
have you great day ahead
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