Question

A person moves a distance of 7 km towards east and takes a turn and then moves 9 km towards west. Find the distance covered by the person and displacement of his motion.​

Answer 1

Answer:

1.41km South-east

Explanation:

The magnitude of the displacement is clearly equal to the length x shown on the figure.

As it is a right angle triangle ,we can use Pythagoras theorem to find x

a^2= b^2+c^2 hence

x^2=1^2+1^2

x= square root(2)

x=1.41 km to two decimal places .

No it’s not over yet.

Let’s find the direction. We can express the direction as an angle from the horizontal. The angle shown in the diagram is theta.

To find theta just use some trigonometry.

tan (theta)= 1/1

theta= tan inverse(1)

theta= 45 degrees.

Now that we have found both the magnitude and the direction of the displacement ,we can finally present the answer.

Displacement of the man is

1.41 km at 45 degrees from the horizontal.

Better put it simply as North east

So displacement of the man is

1.41 km North east.

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Answer 2

The magnitude of the displacement is clearly equal to the length x shown on the figure.

As it is a right angle triangle ,we can use Pythagoras theorem to find x

a^2= b^2+c^2 hence

x^2=1^2+1^2

x= square root(2)

x=1.41 km to two decimal places .

No it’s not over yet.

Let’s find the direction. We can express the direction as an angle from the horizontal. The angle shown in the diagram is theta.

To find theta just use some trigonometry.

tan (theta)= 1/1

theta= tan inverse(1)

theta= 45 degrees.

Now that we have found both the magnitude and the direction of the displacement ,we can finally present the answer.

Displacement of the man is

1.41 km at 45 degrees from the horizontal.

Better put it simply as North east

So displacement of the man is

1.41 km North east.