Question

a person moves along a boundary of a square park of side 10 m in 40 s .what will be displacement of the person at the end of 3 minutes.
please answer this question with explanation ​

Answer 1

Answer:

a person completed 4.5 rounds in 3 minutes.

Magnitude of displacement=

= {10}^{2} + {10}^{2}=10

2

+10

2

= 100 + 100=100+100

= 200=200

= \sqrt{200}=

200

= 10 \sqrt{2} m=10

2

m

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