Question

A person moves from A to B(a distance of 50m)and returns back to A in 1minute 40second.What is the average speed of the person?

Answer 1

${\pink{\mathbb{Hola!!}}}$

Average Speed=${\frac{Total\: Distance}{Total\:time}}$

Distance=50+50
=100 m

time=1 min 40 sec
=1×60+40 sec
=60+40
=100 sec

Average speed =${\frac{100}{100}}$

Average speed =1 m/s

Answer 2

Answer:

Speed= Distance / time

Distance = 50+ 50 ( because he goes to 'A' of distance 50 m and come back from' B' to 'A' so the distance will be 100 m)

Speed = 100/100

= 1

So the average speed of the person will be 1 m/s per second