Question

a person moves from A to D along the circular path A,B,C,D as shown in figure in time 2 s .then the magnitude of average velocity of the person is​

Answer 1

As it's a right angled triangle

Answer 2

Answer:

we know, average velocity = displacement/time

Here, displacement can be taken by pythagoarain theoram and time is given.

Explanation:

Displacement =

$\sqrt{ {10}^{2} + {10}^{2} }$

=

$\sqrt{100 + 100}$

=

$\sqrt{200}$

=

$10 \sqrt{2}$

Now, we know average velocity is equal to

Displacement / time

Average velocity =

$10 \sqrt{2} \div \sqrt{2}$

= 10 m/s Ans