Question

A person moves from point a to b by covering a distance of 100m in 10 seconds and comes back to point a in 20 seconds. Find a) Distance covered by him. b) Displacement made by him. c) Find the speed in kilometre per hour. d) Find the velocity of that person. ​

Answer 1

ANSWER

From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=TimetakenDistance covered=150300=2 m/sec

Average velocity=TimetakenDisplacement=150300=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=TimetakenDistance covered=210400=1.90 m/sec

Average velocity=TimetakenDisplacement=210200=0.95 m/sec

I hope this is helpful for all.

Answer 2

Answer:

a) total distance is (100+100)=200

b) starting and ending point is same so

displacement is 0

c) speed=total distance/ total time

= 200/(10+20)

=200/30

=20/3 m/s

=(20/3)(18/5)

=360/15

= 24km/hr

d) velocity = displacement /time

= 0/30

=0 m/s

Step-by-step explanation:

hope it will help u.....666.....