a person moves from point O to A distance 10 Km in 1h 30min. then return back to a point C such that AC is equal to 4Km. Find his average speed and average velocity.
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Speed of car in first 15 minutes = 40 km/h
Distance covered = speed × Time taken
60 minutes = 1 hour
15 minutes =
60
15
hour
Distance covered = 240×
60
15
=10km
Speed of car in next 15 minutes = 60 km/h
Distance covered = 60×
60
15
=15km
∴ Total distance covered = (10+15)km = 25 km
∴ 25 km is correct
I hope you are understand my solution
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