a person moves on a semicircular track of radius 40 metre if he starts at one end of a track and reaches the other find the distance covered and magnitude of displacement of the person
Answers
Answered by
5
Answer:
the distance traveled will be 1/2 of 2πr = 1/2×2× 3.14 × 40 = 125.60 meters and magnitude displacement will be 40 meters
Answered by
1
SORRY , CAN YOU PLEASE PUT 40 INSTEAD OF 20
actually I put 20 m in place of 40 m for the radius .
so sorry
Now , your distance will be 125.7m .
dispacement= 80m .
MARK ME AS BRAINLIEST PLEASE .
Attachments:
![](https://hi-static.z-dn.net/files/dc4/600c6698e5a864e8067dc82748e6c613.jpg)
![](https://hi-static.z-dn.net/files/d05/fa60b344bb3c353bc4bf0a3cde112653.jpg)
Similar questions