Physics, asked by kavyashivling, 10 months ago

A person moves towards east for 3m , then towards north for 4m and then moves vertically up by 5m what is his distance now from the starting point?

Answers

Answered by tanyguy
4

Explanation:

the distance would be the diagonal of the cuboid

√(l^2+b^2+h^2)

√(3^2 + 4^2 + 5^2)

√(9 + 16 + 25)

√(50)

5√2

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