Question

A person moves towards east for 3m, then towards north for 4m and then moves vertically up by 5m .?

what is his distance now from the starting point? 

Answer 1

this is a right answer and we need to clear our concept

Answer 2

Given,

Distance covered in east direction = 3 metres

Distance covered in north direction = 4 metres

Distance covered in vertically upward direction = 5 metres

To find,

Distance between the starting point and the end point.

Solution,

Let,the starting point = A

Then he covered a distance of 3 metres in the east direction to reach the point B.

After that,he coverd a distance of 4 metres in the north direction to reach the point C.

At last, he covered a distance of 5 metres in the vertically upward direction to reach the point D. (Everything is elaborated in the attached diagram.)

So,we need to calculate the length of AD.

Now, if we compare the AB and BC as the base and height of a right angle triangle,then the hypotenuse of that right angle triangle will be the AC.

According to the Pythagoras theorem;

(AB)²+(BC)² = (AC)²

(3)²+(4)²= (AC)²

9+16 = (AC)²

(AC)² = 25

AC = 5

So,the length of AC = 5 metres

Now,if we compare AC and CD as the base and height of a right angle triangle,then the AD will be the hypotenuse of that right angle triangle.

According to the Pythagoras theorem,

(AC)² + (CD)² = (AD)²

(5)²+(5)² = (AD)²

(AD)² = 50

AD = 5✓2

Hence,he is 5✓2 metres away from the starting point.