Physics, asked by Bky841202, 1 year ago

A person moves towards East for 3m then towards North for4m and then moves vertically up by 5 m. What is his distance now from the starting point?

Answers

Answered by himanshuanand2419
1

Answer:

10 km

Explanation:

as the person move 3 m east and 4 m north it forms a right angled triangle .

acording to Pythagoras theorem a square+ b square= c square

3 square+ 4 square = c square

so c is 5

as he moves 5m vertically up the total distance from the starting point is 10m.

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