Question

A person moves towards north with uniform
speed of 15 m/s and cover 16 m. After this he
moves towards east and covers 6 m and finally
covers 8 m distance with same speed in south.
Find out
(i) Distance travelled by person
(ii) Displacement of person
(iii) Average velocity of person​

Answer 1

Answer:

your answer is

Explanation:

1) distance is=16+6+8

=30m

2) displacement is=√8²+6²=√100

=10m

3)Vavg.=total distance /total time

total time =

(16/15 )+ (6/15)+ (8/15) =30/15

=30*15/30 =15m/s

hope it will help u plz mark as brainliest answer

Answer 2

Answer:

(i) Distance: 30m

(ii) Displacement: 10m

(iii) Avg Velocity: 5m/s

Explanation:

(i) From the diagram;

Distance= AB+BC+CD

Distance= 16+6+8

So, Distance= 30m

(ii) From the diagram, the displacement of a person can be considered as AD. Now;

CD=OB= 8m

BC=OD= 6m

OA=AB-OB= 16-8 =8m

In ∆AOD; AD= √(OA)²+(OD)²

AD= √(8)²+(6)²

AD= √100 = 10m

Therefore; Displacement is 10m

(iii) Time=Distance/Speed

Time= 30/15 = 2seconds

Now;

Avg Velocity= Total Displacement/Total Time

Avg Velocity= 10/2 = 5m/s

The direction of velocity will be same as direction of displacement. Dis.(OA): North! Dis.(OD): East!

Applying ∆ Law; Direction Of Displacement/Velocity is towards North East.

So, Avg Velocity= 5m/s of North East!

Hope It Helps!